3(b+b+b+5)=32

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Solution for 3(b+b+b+5)=32 equation: 



3(b+b+b+5)=32

We move all terms to the left:

3(b+b+b+5)-(32)=0

We add all the numbers together, and all the variables

3(3b+5)-32=0

We multiply parentheses

9b+15-32=0

We add all the numbers together, and all the variables

9b-17=0

We move all terms containing b to the left, all other terms to the right

9b=17

b=17/9

b=1+8/9

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