3(b-1)+2(b+3)=13

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Solution for 3(b-1)+2(b+3)=13 equation: 



3(b-1)+2(b+3)=13

We move all terms to the left:

3(b-1)+2(b+3)-(13)=0

We multiply parentheses

3b+2b-3+6-13=0

We add all the numbers together, and all the variables

5b-10=0

We move all terms containing b to the left, all other terms to the right

5b=10

b=10/5

b=2

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