3(b-1)-5(b+2)=9

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Solution for 3(b-1)-5(b+2)=9 equation: 



3(b-1)-5(b+2)=9

We move all terms to the left:

3(b-1)-5(b+2)-(9)=0

We multiply parentheses

3b-5b-3-10-9=0

We add all the numbers together, and all the variables

-2b-22=0

We move all terms containing b to the left, all other terms to the right

-2b=22

b=22/-2

b=-11

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