3(b-1)-7b=-5(-3-2b)+24

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Solution for 3(b-1)-7b=-5(-3-2b)+24 equation: 



3(b-1)-7b=-5(-3-2b)+24

We move all terms to the left:

3(b-1)-7b-(-5(-3-2b)+24)=0

We add all the numbers together, and all the variables

3(b-1)-7b-(-5(-2b-3)+24)=0

We add all the numbers together, and all the variables

-7b+3(b-1)-(-5(-2b-3)+24)=0

We multiply parentheses

-7b+3b-(-5(-2b-3)+24)-3=0



We calculate terms in parentheses: -(-5(-2b-3)+24), so:

-5(-2b-3)+24

We multiply parentheses

10b+15+24

We add all the numbers together, and all the variables

10b+39

Back to the equation:

-(10b+39)



We add all the numbers together, and all the variables

-4b-(10b+39)-3=0

We get rid of parentheses

-4b-10b-39-3=0

We add all the numbers together, and all the variables

-14b-42=0

We move all terms containing b to the left, all other terms to the right

-14b=42

b=42/-14

b=-3

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