3(b-1)=11+b

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Solution for 3(b-1)=11+b equation: 



3(b-1)=11+b

We move all terms to the left:

3(b-1)-(11+b)=0

We add all the numbers together, and all the variables

3(b-1)-(b+11)=0

We multiply parentheses

3b-(b+11)-3=0

We get rid of parentheses

3b-b-11-3=0

We add all the numbers together, and all the variables

2b-14=0

We move all terms containing b to the left, all other terms to the right

2b=14

b=14/2

b=7

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