3(b-1)=2(b+1)

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Solution for 3(b-1)=2(b+1) equation: 



3(b-1)=2(b+1)

We move all terms to the left:

3(b-1)-(2(b+1))=0

We multiply parentheses

3b-(2(b+1))-3=0



We calculate terms in parentheses: -(2(b+1)), so:

2(b+1)

We multiply parentheses

2b+2

Back to the equation:

-(2b+2)



We get rid of parentheses

3b-2b-2-3=0

We add all the numbers together, and all the variables

b-5=0

We move all terms containing b to the left, all other terms to the right

b=5

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