3(b-1)=7(-2b+2)

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Solution for 3(b-1)=7(-2b+2) equation:



3(b-1)=7(-2b+2)
We move all terms to the left:
3(b-1)-(7(-2b+2))=0
We multiply parentheses
3b-(7(-2b+2))-3=0
We calculate terms in parentheses: -(7(-2b+2)), so:
7(-2b+2)
We multiply parentheses
-14b+14
Back to the equation:
-(-14b+14)
We get rid of parentheses
3b+14b-14-3=0
We add all the numbers together, and all the variables
17b-17=0
We move all terms containing b to the left, all other terms to the right
17b=17
b=17/17
b=1

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