3(b-1)=7b+2

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Solution for 3(b-1)=7b+2 equation: 



3(b-1)=7b+2

We move all terms to the left:

3(b-1)-(7b+2)=0

We multiply parentheses

3b-(7b+2)-3=0

We get rid of parentheses

3b-7b-2-3=0

We add all the numbers together, and all the variables

-4b-5=0

We move all terms containing b to the left, all other terms to the right

-4b=5

b=5/-4

b=-1+1/4

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