3(b-10)+4(b-18)=10

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Solution for 3(b-10)+4(b-18)=10 equation: 



3(b-10)+4(b-18)=10

We move all terms to the left:

3(b-10)+4(b-18)-(10)=0

We multiply parentheses

3b+4b-30-72-10=0

We add all the numbers together, and all the variables

7b-112=0

We move all terms containing b to the left, all other terms to the right

7b=112

b=112/7

b=16

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