3(b-10)=-30+3b

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Solution for 3(b-10)=-30+3b equation: 



3(b-10)=-30+3b

We move all terms to the left:

3(b-10)-(-30+3b)=0

We add all the numbers together, and all the variables

3(b-10)-(3b-30)=0

We multiply parentheses

3b-(3b-30)-30=0

We get rid of parentheses

3b-3b+30-30=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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