3(b-2)+2(b-3)=5

Solution for 3(b-2)+2(b-3)=5 equation:

Simplifying
3(b + -2) + 2(b + -3) = 5

Reorder the terms:
3(-2 + b) + 2(b + -3) = 5
(-2 * 3 + b * 3) + 2(b + -3) = 5
(-6 + 3b) + 2(b + -3) = 5

Reorder the terms:
-6 + 3b + 2(-3 + b) = 5
-6 + 3b + (-3 * 2 + b * 2) = 5
-6 + 3b + (-6 + 2b) = 5

Reorder the terms:
-6 + -6 + 3b + 2b = 5

Combine like terms: -6 + -6 = -12
-12 + 3b + 2b = 5

Combine like terms: 3b + 2b = 5b
-12 + 5b = 5

Solving
-12 + 5b = 5

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 5b = 5 + 12

Combine like terms: -12 + 12 = 0
0 + 5b = 5 + 12
5b = 5 + 12

Combine like terms: 5 + 12 = 17
5b = 17

Divide each side by '5'.
b = 3.4

Simplifying
b = 3.4