3(b-2)+6(b+1)=0

Solution for 3(b-2)+6(b+1)=0 equation:

Simplifying
3(b + -2) + 6(b + 1) = 0

Reorder the terms:
3(-2 + b) + 6(b + 1) = 0
(-2 * 3 + b * 3) + 6(b + 1) = 0
(-6 + 3b) + 6(b + 1) = 0

Reorder the terms:
-6 + 3b + 6(1 + b) = 0
-6 + 3b + (1 * 6 + b * 6) = 0
-6 + 3b + (6 + 6b) = 0

Reorder the terms:
-6 + 6 + 3b + 6b = 0

Combine like terms: -6 + 6 = 0
0 + 3b + 6b = 0
3b + 6b = 0

Combine like terms: 3b + 6b = 9b
9b = 0

Solving
9b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Divide each side by '9'.
b = 0

Simplifying
b = 0