3(b-2)+b=4

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Solution for 3(b-2)+b=4 equation: 



3(b-2)+b=4

We move all terms to the left:

3(b-2)+b-(4)=0

We add all the numbers together, and all the variables

b+3(b-2)-4=0

We multiply parentheses

b+3b-6-4=0

We add all the numbers together, and all the variables

4b-10=0

We move all terms containing b to the left, all other terms to the right

4b=10

b=10/4

b=2+1/2

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