3(b-2)-1=4(b-3)

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Solution for 3(b-2)-1=4(b-3) equation:


Simplifying
3(b + -2) + -1 = 4(b + -3)

Reorder the terms:
3(-2 + b) + -1 = 4(b + -3)
(-2 * 3 + b * 3) + -1 = 4(b + -3)
(-6 + 3b) + -1 = 4(b + -3)

Reorder the terms:
-6 + -1 + 3b = 4(b + -3)

Combine like terms: -6 + -1 = -7
-7 + 3b = 4(b + -3)

Reorder the terms:
-7 + 3b = 4(-3 + b)
-7 + 3b = (-3 * 4 + b * 4)
-7 + 3b = (-12 + 4b)

Solving
-7 + 3b = -12 + 4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
-7 + 3b + -4b = -12 + 4b + -4b

Combine like terms: 3b + -4b = -1b
-7 + -1b = -12 + 4b + -4b

Combine like terms: 4b + -4b = 0
-7 + -1b = -12 + 0
-7 + -1b = -12

Add '7' to each side of the equation.
-7 + 7 + -1b = -12 + 7

Combine like terms: -7 + 7 = 0
0 + -1b = -12 + 7
-1b = -12 + 7

Combine like terms: -12 + 7 = -5
-1b = -5

Divide each side by '-1'.
b = 5

Simplifying
b = 5

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