3(b-2)-4(b-3)=5b

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Solution for 3(b-2)-4(b-3)=5b equation:



3(b-2)-4(b-3)=5b
We move all terms to the left:
3(b-2)-4(b-3)-(5b)=0
We add all the numbers together, and all the variables
-5b+3(b-2)-4(b-3)=0
We multiply parentheses
-5b+3b-4b-6+12=0
We add all the numbers together, and all the variables
-6b+6=0
We move all terms containing b to the left, all other terms to the right
-6b=-6
b=-6/-6
b=1

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