3(b-2)-4(b-3)=5b

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Solution for 3(b-2)-4(b-3)=5b equation: 



3(b-2)-4(b-3)=5b

We move all terms to the left:

3(b-2)-4(b-3)-(5b)=0

We add all the numbers together, and all the variables

-5b+3(b-2)-4(b-3)=0

We multiply parentheses

-5b+3b-4b-6+12=0

We add all the numbers together, and all the variables

-6b+6=0

We move all terms containing b to the left, all other terms to the right

-6b=-6

b=-6/-6

b=1

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