3(b-2)=12

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Solution for 3(b-2)=12 equation: 



3(b-2)=12

We move all terms to the left:

3(b-2)-(12)=0

We multiply parentheses

3b-6-12=0

We add all the numbers together, and all the variables

3b-18=0

We move all terms containing b to the left, all other terms to the right

3b=18

b=18/3

b=6

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