3(b-2)=2(b+2k)

Solution for 3(b-2)=2(b+2k) equation:

Simplifying
3(b + -2) = 2(b + 2k)

Reorder the terms:
3(-2 + b) = 2(b + 2k)
(-2 * 3 + b * 3) = 2(b + 2k)
(-6 + 3b) = 2(b + 2k)
-6 + 3b = (b * 2 + 2k * 2)
-6 + 3b = (2b + 4k)

Solving
-6 + 3b = 2b + 4k

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
-6 + 3b + -2b = 2b + -2b + 4k

Combine like terms: 3b + -2b = 1b
-6 + 1b = 2b + -2b + 4k

Combine like terms: 2b + -2b = 0
-6 + 1b = 0 + 4k
-6 + 1b = 4k

Add '6' to each side of the equation.
-6 + 6 + 1b = 6 + 4k

Combine like terms: -6 + 6 = 0
0 + 1b = 6 + 4k
1b = 6 + 4k

Divide each side by '1'.
b = 6 + 4k

Simplifying
b = 6 + 4k