3(b-2)=5(9+b)

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Solution for 3(b-2)=5(9+b) equation: 



3(b-2)=5(9+b)

We move all terms to the left:

3(b-2)-(5(9+b))=0

We add all the numbers together, and all the variables

3(b-2)-(5(b+9))=0

We multiply parentheses

3b-(5(b+9))-6=0



We calculate terms in parentheses: -(5(b+9)), so:

5(b+9)

We multiply parentheses

5b+45

Back to the equation:

-(5b+45)



We get rid of parentheses

3b-5b-45-6=0

We add all the numbers together, and all the variables

-2b-51=0

We move all terms containing b to the left, all other terms to the right

-2b=51

b=51/-2

b=-25+1/2

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