3(b-2)=5(b+5)-15

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Solution for 3(b-2)=5(b+5)-15 equation:


Simplifying
3(b + -2) = 5(b + 5) + -15

Reorder the terms:
3(-2 + b) = 5(b + 5) + -15
(-2 * 3 + b * 3) = 5(b + 5) + -15
(-6 + 3b) = 5(b + 5) + -15

Reorder the terms:
-6 + 3b = 5(5 + b) + -15
-6 + 3b = (5 * 5 + b * 5) + -15
-6 + 3b = (25 + 5b) + -15

Reorder the terms:
-6 + 3b = 25 + -15 + 5b

Combine like terms: 25 + -15 = 10
-6 + 3b = 10 + 5b

Solving
-6 + 3b = 10 + 5b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5b' to each side of the equation.
-6 + 3b + -5b = 10 + 5b + -5b

Combine like terms: 3b + -5b = -2b
-6 + -2b = 10 + 5b + -5b

Combine like terms: 5b + -5b = 0
-6 + -2b = 10 + 0
-6 + -2b = 10

Add '6' to each side of the equation.
-6 + 6 + -2b = 10 + 6

Combine like terms: -6 + 6 = 0
0 + -2b = 10 + 6
-2b = 10 + 6

Combine like terms: 10 + 6 = 16
-2b = 16

Divide each side by '-2'.
b = -8

Simplifying
b = -8

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