3(b-21)+3(b-4)=21

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Solution for 3(b-21)+3(b-4)=21 equation: 



3(b-21)+3(b-4)=21

We move all terms to the left:

3(b-21)+3(b-4)-(21)=0

We multiply parentheses

3b+3b-63-12-21=0

We add all the numbers together, and all the variables

6b-96=0

We move all terms containing b to the left, all other terms to the right

6b=96

b=96/6

b=16

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