3(b-24)+2(b-4)=0

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Solution for 3(b-24)+2(b-4)=0 equation: 



3(b-24)+2(b-4)=0

We multiply parentheses

3b+2b-72-8=0

We add all the numbers together, and all the variables

5b-80=0

We move all terms containing b to the left, all other terms to the right

5b=80

b=80/5

b=16

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