3(b-3)(b+3)=0

Solution for 3(b-3)(b+3)=0 equation:

Simplifying
3(b + -3)(b + 3) = 0

Reorder the terms:
3(-3 + b)(b + 3) = 0

Reorder the terms:
3(-3 + b)(3 + b) = 0

Multiply (-3 + b) * (3 + b)
3(-3(3 + b) + b(3 + b)) = 0
3((3 * -3 + b * -3) + b(3 + b)) = 0
3((-9 + -3b) + b(3 + b)) = 0
3(-9 + -3b + (3 * b + b * b)) = 0
3(-9 + -3b + (3b + b2)) = 0

Combine like terms: -3b + 3b = 0
3(-9 + 0 + b2) = 0
3(-9 + b2) = 0
(-9 * 3 + b2 * 3) = 0
(-27 + 3b2) = 0

Solving
-27 + 3b2 = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '27' to each side of the equation.
-27 + 27 + 3b2 = 0 + 27

Combine like terms: -27 + 27 = 0
0 + 3b2 = 0 + 27
3b2 = 0 + 27

Combine like terms: 0 + 27 = 27
3b2 = 27

Divide each side by '3'.
b2 = 9

Simplifying
b2 = 9

Take the square root of each side:
b = {-3, 3}