3(b-3)+2=4(b+3)

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Solution for 3(b-3)+2=4(b+3) equation:



3(b-3)+2=4(b+3)
We move all terms to the left:
3(b-3)+2-(4(b+3))=0
We multiply parentheses
3b-(4(b+3))-9+2=0
We calculate terms in parentheses: -(4(b+3)), so:
4(b+3)
We multiply parentheses
4b+12
Back to the equation:
-(4b+12)
We add all the numbers together, and all the variables
3b-(4b+12)-7=0
We get rid of parentheses
3b-4b-12-7=0
We add all the numbers together, and all the variables
-1b-19=0
We move all terms containing b to the left, all other terms to the right
-b=19
b=19/-1
b=-19

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