3(b-3)+5=4(b-1)

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Solution for 3(b-3)+5=4(b-1) equation:


Simplifying
3(b + -3) + 5 = 4(b + -1)

Reorder the terms:
3(-3 + b) + 5 = 4(b + -1)
(-3 * 3 + b * 3) + 5 = 4(b + -1)
(-9 + 3b) + 5 = 4(b + -1)

Reorder the terms:
-9 + 5 + 3b = 4(b + -1)

Combine like terms: -9 + 5 = -4
-4 + 3b = 4(b + -1)

Reorder the terms:
-4 + 3b = 4(-1 + b)
-4 + 3b = (-1 * 4 + b * 4)
-4 + 3b = (-4 + 4b)

Add '4' to each side of the equation.
-4 + 4 + 3b = -4 + 4 + 4b

Combine like terms: -4 + 4 = 0
0 + 3b = -4 + 4 + 4b
3b = -4 + 4 + 4b

Combine like terms: -4 + 4 = 0
3b = 0 + 4b
3b = 4b

Solving
3b = 4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
3b + -4b = 4b + -4b

Combine like terms: 3b + -4b = -1b
-1b = 4b + -4b

Combine like terms: 4b + -4b = 0
-1b = 0

Divide each side by '-1'.
b = 0

Simplifying
b = 0

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