3(b-3)-2(b-3)=2b-3

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Solution for 3(b-3)-2(b-3)=2b-3 equation:


Simplifying
3(b + -3) + -2(b + -3) = 2b + -3

Reorder the terms:
3(-3 + b) + -2(b + -3) = 2b + -3
(-3 * 3 + b * 3) + -2(b + -3) = 2b + -3
(-9 + 3b) + -2(b + -3) = 2b + -3

Reorder the terms:
-9 + 3b + -2(-3 + b) = 2b + -3
-9 + 3b + (-3 * -2 + b * -2) = 2b + -3
-9 + 3b + (6 + -2b) = 2b + -3

Reorder the terms:
-9 + 6 + 3b + -2b = 2b + -3

Combine like terms: -9 + 6 = -3
-3 + 3b + -2b = 2b + -3

Combine like terms: 3b + -2b = 1b
-3 + 1b = 2b + -3

Reorder the terms:
-3 + 1b = -3 + 2b

Add '3' to each side of the equation.
-3 + 3 + 1b = -3 + 3 + 2b

Combine like terms: -3 + 3 = 0
0 + 1b = -3 + 3 + 2b
1b = -3 + 3 + 2b

Combine like terms: -3 + 3 = 0
1b = 0 + 2b
1b = 2b

Solving
1b = 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
1b + -2b = 2b + -2b

Combine like terms: 1b + -2b = -1b
-1b = 2b + -2b

Combine like terms: 2b + -2b = 0
-1b = 0

Divide each side by '-1'.
b = 0

Simplifying
b = 0

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