3(b-3)=2(b+12)

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Solution for 3(b-3)=2(b+12) equation: 



3(b-3)=2(b+12)

We move all terms to the left:

3(b-3)-(2(b+12))=0

We multiply parentheses

3b-(2(b+12))-9=0



We calculate terms in parentheses: -(2(b+12)), so:

2(b+12)

We multiply parentheses

2b+24

Back to the equation:

-(2b+24)



We get rid of parentheses

3b-2b-24-9=0

We add all the numbers together, and all the variables

b-33=0

We move all terms containing b to the left, all other terms to the right

b=33

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