3(b-3)=2(b+4)

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Solution for 3(b-3)=2(b+4) equation: 



3(b-3)=2(b+4)

We move all terms to the left:

3(b-3)-(2(b+4))=0

We multiply parentheses

3b-(2(b+4))-9=0



We calculate terms in parentheses: -(2(b+4)), so:

2(b+4)

We multiply parentheses

2b+8

Back to the equation:

-(2b+8)



We get rid of parentheses

3b-2b-8-9=0

We add all the numbers together, and all the variables

b-17=0

We move all terms containing b to the left, all other terms to the right

b=17

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