3(b-3)=20b-3

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Solution for 3(b-3)=20b-3 equation: 



3(b-3)=20b-3

We move all terms to the left:

3(b-3)-(20b-3)=0

We multiply parentheses

3b-(20b-3)-9=0

We get rid of parentheses

3b-20b+3-9=0

We add all the numbers together, and all the variables

-17b-6=0

We move all terms containing b to the left, all other terms to the right

-17b=6

b=6/-17

b=-6/17

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