3(b-4)+3=-2b+5b-9

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Solution for 3(b-4)+3=-2b+5b-9 equation: 


Simplifying
3(b + -4) + 3 = -2b + 5b + -9

Reorder the terms:
3(-4 + b) + 3 = -2b + 5b + -9
(-4 * 3 + b * 3) + 3 = -2b + 5b + -9
(-12 + 3b) + 3 = -2b + 5b + -9

Reorder the terms:
-12 + 3 + 3b = -2b + 5b + -9

Combine like terms: -12 + 3 = -9
-9 + 3b = -2b + 5b + -9

Reorder the terms:
-9 + 3b = -9 + -2b + 5b

Combine like terms: -2b + 5b = 3b
-9 + 3b = -9 + 3b

Add '9' to each side of the equation.
-9 + 9 + 3b = -9 + 9 + 3b

Combine like terms: -9 + 9 = 0
0 + 3b = -9 + 9 + 3b
3b = -9 + 9 + 3b

Combine like terms: -9 + 9 = 0
3b = 0 + 3b
3b = 3b

Add '-3b' to each side of the equation.
3b + -3b = 3b + -3b

Combine like terms: 3b + -3b = 0
0 = 3b + -3b

Combine like terms: 3b + -3b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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