3(b-4)+6=5(b-1)+1

Solution for 3(b-4)+6=5(b-1)+1 equation:

Simplifying
3(b + -4) + 6 = 5(b + -1) + 1

Reorder the terms:
3(-4 + b) + 6 = 5(b + -1) + 1
(-4 * 3 + b * 3) + 6 = 5(b + -1) + 1
(-12 + 3b) + 6 = 5(b + -1) + 1

Reorder the terms:
-12 + 6 + 3b = 5(b + -1) + 1

Combine like terms: -12 + 6 = -6
-6 + 3b = 5(b + -1) + 1

Reorder the terms:
-6 + 3b = 5(-1 + b) + 1
-6 + 3b = (-1 * 5 + b * 5) + 1
-6 + 3b = (-5 + 5b) + 1

Reorder the terms:
-6 + 3b = -5 + 1 + 5b

Combine like terms: -5 + 1 = -4
-6 + 3b = -4 + 5b

Solving
-6 + 3b = -4 + 5b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5b' to each side of the equation.
-6 + 3b + -5b = -4 + 5b + -5b

Combine like terms: 3b + -5b = -2b
-6 + -2b = -4 + 5b + -5b

Combine like terms: 5b + -5b = 0
-6 + -2b = -4 + 0
-6 + -2b = -4

Add '6' to each side of the equation.
-6 + 6 + -2b = -4 + 6

Combine like terms: -6 + 6 = 0
0 + -2b = -4 + 6
-2b = -4 + 6

Combine like terms: -4 + 6 = 2
-2b = 2

Divide each side by '-2'.
b = -1

Simplifying
b = -1