3(b-4)-2(b+4)=

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Solution for 3(b-4)-2(b+4)= equation: 



3(b-4)-2(b+4)=

We move all terms to the left:

3(b-4)-2(b+4)-()=0

We add all the numbers together, and all the variables

3(b-4)-2(b+4)=0

We multiply parentheses

3b-2b-12-8=0

We add all the numbers together, and all the variables

b-20=0

We move all terms containing b to the left, all other terms to the right

b=20

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