3(b-4)-2(b+4)=

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Solution for 3(b-4)-2(b+4)= equation:



3(b-4)-2(b+4)=
We move all terms to the left:
3(b-4)-2(b+4)-()=0
We add all the numbers together, and all the variables
3(b-4)-2(b+4)=0
We multiply parentheses
3b-2b-12-8=0
We add all the numbers together, and all the variables
b-20=0
We move all terms containing b to the left, all other terms to the right
b=20

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