3(b-4)-2(b+4)=6

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Solution for 3(b-4)-2(b+4)=6 equation:


Simplifying
3(b + -4) + -2(b + 4) = 6

Reorder the terms:
3(-4 + b) + -2(b + 4) = 6
(-4 * 3 + b * 3) + -2(b + 4) = 6
(-12 + 3b) + -2(b + 4) = 6

Reorder the terms:
-12 + 3b + -2(4 + b) = 6
-12 + 3b + (4 * -2 + b * -2) = 6
-12 + 3b + (-8 + -2b) = 6

Reorder the terms:
-12 + -8 + 3b + -2b = 6

Combine like terms: -12 + -8 = -20
-20 + 3b + -2b = 6

Combine like terms: 3b + -2b = 1b
-20 + 1b = 6

Solving
-20 + 1b = 6

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '20' to each side of the equation.
-20 + 20 + 1b = 6 + 20

Combine like terms: -20 + 20 = 0
0 + 1b = 6 + 20
1b = 6 + 20

Combine like terms: 6 + 20 = 26
1b = 26

Divide each side by '1'.
b = 26

Simplifying
b = 26

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