3(b-4)-5b=2

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Solution for 3(b-4)-5b=2 equation: 



3(b-4)-5b=2

We move all terms to the left:

3(b-4)-5b-(2)=0

We add all the numbers together, and all the variables

-5b+3(b-4)-2=0

We multiply parentheses

-5b+3b-12-2=0

We add all the numbers together, and all the variables

-2b-14=0

We move all terms containing b to the left, all other terms to the right

-2b=14

b=14/-2

b=-7

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