3(b-4)=-11+4b

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Solution for 3(b-4)=-11+4b equation: 



3(b-4)=-11+4b

We move all terms to the left:

3(b-4)-(-11+4b)=0

We add all the numbers together, and all the variables

3(b-4)-(4b-11)=0

We multiply parentheses

3b-(4b-11)-12=0

We get rid of parentheses

3b-4b+11-12=0

We add all the numbers together, and all the variables

-1b-1=0

We move all terms containing b to the left, all other terms to the right

-b=1

b=1/-1

b=-1

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