3(b-4)=-12+8b

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Solution for 3(b-4)=-12+8b equation: 



3(b-4)=-12+8b

We move all terms to the left:

3(b-4)-(-12+8b)=0

We add all the numbers together, and all the variables

3(b-4)-(8b-12)=0

We multiply parentheses

3b-(8b-12)-12=0

We get rid of parentheses

3b-8b+12-12=0

We add all the numbers together, and all the variables

-5b=0

b=0/-5

b=0

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