3(b-4)=2(b+2)

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Solution for 3(b-4)=2(b+2) equation:


Simplifying
3(b + -4) = 2(b + 2)

Reorder the terms:
3(-4 + b) = 2(b + 2)
(-4 * 3 + b * 3) = 2(b + 2)
(-12 + 3b) = 2(b + 2)

Reorder the terms:
-12 + 3b = 2(2 + b)
-12 + 3b = (2 * 2 + b * 2)
-12 + 3b = (4 + 2b)

Solving
-12 + 3b = 4 + 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
-12 + 3b + -2b = 4 + 2b + -2b

Combine like terms: 3b + -2b = 1b
-12 + 1b = 4 + 2b + -2b

Combine like terms: 2b + -2b = 0
-12 + 1b = 4 + 0
-12 + 1b = 4

Add '12' to each side of the equation.
-12 + 12 + 1b = 4 + 12

Combine like terms: -12 + 12 = 0
0 + 1b = 4 + 12
1b = 4 + 12

Combine like terms: 4 + 12 = 16
1b = 16

Divide each side by '1'.
b = 16

Simplifying
b = 16

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