3(b-4)=20

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Solution for 3(b-4)=20 equation: 



3(b-4)=20

We move all terms to the left:

3(b-4)-(20)=0

We multiply parentheses

3b-12-20=0

We add all the numbers together, and all the variables

3b-32=0

We move all terms containing b to the left, all other terms to the right

3b=32

b=32/3

b=10+2/3

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