3(b-4)=3b-12

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Solution for 3(b-4)=3b-12 equation: 



3(b-4)=3b-12

We move all terms to the left:

3(b-4)-(3b-12)=0

We multiply parentheses

3b-(3b-12)-12=0

We get rid of parentheses

3b-3b+12-12=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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