3(b-4)=8b+8

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Solution for 3(b-4)=8b+8 equation:



3(b-4)=8b+8
We move all terms to the left:
3(b-4)-(8b+8)=0
We multiply parentheses
3b-(8b+8)-12=0
We get rid of parentheses
3b-8b-8-12=0
We add all the numbers together, and all the variables
-5b-20=0
We move all terms containing b to the left, all other terms to the right
-5b=20
b=20/-5
b=-4

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