3(b-4)=8b+8

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Solution for 3(b-4)=8b+8 equation: 



3(b-4)=8b+8

We move all terms to the left:

3(b-4)-(8b+8)=0

We multiply parentheses

3b-(8b+8)-12=0

We get rid of parentheses

3b-8b-8-12=0

We add all the numbers together, and all the variables

-5b-20=0

We move all terms containing b to the left, all other terms to the right

-5b=20

b=20/-5

b=-4

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