3(b-4)=b-8

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Solution for 3(b-4)=b-8 equation:


Simplifying
3(b + -4) = b + -8

Reorder the terms:
3(-4 + b) = b + -8
(-4 * 3 + b * 3) = b + -8
(-12 + 3b) = b + -8

Reorder the terms:
-12 + 3b = -8 + b

Solving
-12 + 3b = -8 + b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-1b' to each side of the equation.
-12 + 3b + -1b = -8 + b + -1b

Combine like terms: 3b + -1b = 2b
-12 + 2b = -8 + b + -1b

Combine like terms: b + -1b = 0
-12 + 2b = -8 + 0
-12 + 2b = -8

Add '12' to each side of the equation.
-12 + 12 + 2b = -8 + 12

Combine like terms: -12 + 12 = 0
0 + 2b = -8 + 12
2b = -8 + 12

Combine like terms: -8 + 12 = 4
2b = 4

Divide each side by '2'.
b = 2

Simplifying
b = 2

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