3(b-5)+4(b-25)=4

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Solution for 3(b-5)+4(b-25)=4 equation: 



3(b-5)+4(b-25)=4

We move all terms to the left:

3(b-5)+4(b-25)-(4)=0

We multiply parentheses

3b+4b-15-100-4=0

We add all the numbers together, and all the variables

7b-119=0

We move all terms containing b to the left, all other terms to the right

7b=119

b=119/7

b=17

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