3(b-5)=-2(b-5)

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Solution for 3(b-5)=-2(b-5) equation:


Simplifying
3(b + -5) = -2(b + -5)

Reorder the terms:
3(-5 + b) = -2(b + -5)
(-5 * 3 + b * 3) = -2(b + -5)
(-15 + 3b) = -2(b + -5)

Reorder the terms:
-15 + 3b = -2(-5 + b)
-15 + 3b = (-5 * -2 + b * -2)
-15 + 3b = (10 + -2b)

Solving
-15 + 3b = 10 + -2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '2b' to each side of the equation.
-15 + 3b + 2b = 10 + -2b + 2b

Combine like terms: 3b + 2b = 5b
-15 + 5b = 10 + -2b + 2b

Combine like terms: -2b + 2b = 0
-15 + 5b = 10 + 0
-15 + 5b = 10

Add '15' to each side of the equation.
-15 + 15 + 5b = 10 + 15

Combine like terms: -15 + 15 = 0
0 + 5b = 10 + 15
5b = 10 + 15

Combine like terms: 10 + 15 = 25
5b = 25

Divide each side by '5'.
b = 5

Simplifying
b = 5

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