3(b-5)=19

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Solution for 3(b-5)=19 equation: 



3(b-5)=19

We move all terms to the left:

3(b-5)-(19)=0

We multiply parentheses

3b-15-19=0

We add all the numbers together, and all the variables

3b-34=0

We move all terms containing b to the left, all other terms to the right

3b=34

b=34/3

b=11+1/3

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