3(b-5)=2(b+5)

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Solution for 3(b-5)=2(b+5) equation: 



3(b-5)=2(b+5)

We move all terms to the left:

3(b-5)-(2(b+5))=0

We multiply parentheses

3b-(2(b+5))-15=0



We calculate terms in parentheses: -(2(b+5)), so:

2(b+5)

We multiply parentheses

2b+10

Back to the equation:

-(2b+10)



We get rid of parentheses

3b-2b-10-15=0

We add all the numbers together, and all the variables

b-25=0

We move all terms containing b to the left, all other terms to the right

b=25

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