3(b-5)=28

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Solution for 3(b-5)=28 equation: 



3(b-5)=28

We move all terms to the left:

3(b-5)-(28)=0

We multiply parentheses

3b-15-28=0

We add all the numbers together, and all the variables

3b-43=0

We move all terms containing b to the left, all other terms to the right

3b=43

b=43/3

b=14+1/3

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