3(b-5)=3(4b-6)

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Solution for 3(b-5)=3(4b-6) equation: 



3(b-5)=3(4b-6)

We move all terms to the left:

3(b-5)-(3(4b-6))=0

We multiply parentheses

3b-(3(4b-6))-15=0



We calculate terms in parentheses: -(3(4b-6)), so:

3(4b-6)

We multiply parentheses

12b-18

Back to the equation:

-(12b-18)



We get rid of parentheses

3b-12b+18-15=0

We add all the numbers together, and all the variables

-9b+3=0

We move all terms containing b to the left, all other terms to the right

-9b=-3

b=-3/-9

b=1/3

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