3(b-5)=6(4b-6)

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Solution for 3(b-5)=6(4b-6) equation: 



3(b-5)=6(4b-6)

We move all terms to the left:

3(b-5)-(6(4b-6))=0

We multiply parentheses

3b-(6(4b-6))-15=0



We calculate terms in parentheses: -(6(4b-6)), so:

6(4b-6)

We multiply parentheses

24b-36

Back to the equation:

-(24b-36)



We get rid of parentheses

3b-24b+36-15=0

We add all the numbers together, and all the variables

-21b+21=0

We move all terms containing b to the left, all other terms to the right

-21b=-21

b=-21/-21

b=1

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