3(b-5)=6(b+4)-18

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Solution for 3(b-5)=6(b+4)-18 equation: 



3(b-5)=6(b+4)-18

We move all terms to the left:

3(b-5)-(6(b+4)-18)=0

We multiply parentheses

3b-(6(b+4)-18)-15=0



We calculate terms in parentheses: -(6(b+4)-18), so:

6(b+4)-18

We multiply parentheses

6b+24-18

We add all the numbers together, and all the variables

6b+6

Back to the equation:

-(6b+6)



We get rid of parentheses

3b-6b-6-15=0

We add all the numbers together, and all the variables

-3b-21=0

We move all terms containing b to the left, all other terms to the right

-3b=21

b=21/-3

b=-7

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