3(b-6)=-5-(7+3b)

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Solution for 3(b-6)=-5-(7+3b) equation: 



3(b-6)=-5-(7+3b)

We move all terms to the left:

3(b-6)-(-5-(7+3b))=0

We add all the numbers together, and all the variables

3(b-6)-(-5-(3b+7))=0

We multiply parentheses

3b-(-5-(3b+7))-18=0



We calculate terms in parentheses: -(-5-(3b+7)), so:

-5-(3b+7)

determiningTheFunctionDomain
-(3b+7)-5

We get rid of parentheses

-3b-7-5

We add all the numbers together, and all the variables

-3b-12

Back to the equation:

-(-3b-12)



We get rid of parentheses

3b+3b+12-18=0

We add all the numbers together, and all the variables

6b-6=0

We move all terms containing b to the left, all other terms to the right

6b=6

b=6/6

b=1

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