3(b-6)=27

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Solution for 3(b-6)=27 equation: 



3(b-6)=27

We move all terms to the left:

3(b-6)-(27)=0

We multiply parentheses

3b-18-27=0

We add all the numbers together, and all the variables

3b-45=0

We move all terms containing b to the left, all other terms to the right

3b=45

b=45/3

b=15

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